Program to check whether entered number is armstrong or not.

//An armstrong number is an number in which the sum of cubes of the digits of the number equals the number.
For eg: 153 = 1(1's cube) + 125(5's cube) + 27(3's cube)

#include<stdio.h>
#include<conio.h>

void armstrong();                             //Function declaration

void main()
{
        int num, a;
        printf("\nEnter an integer number: ");
        scanf("%d", &num);
        armstrong(num);                  //Function call
        getch();
}
void armstrong(int p)
{
        int t, cube, scube=0, d;
        t=p;
        while(p>0)
{
                d=p%10;                     //Separating digit's
                cube=d*d*d;               //Cube of separated digit
                scube=scube+cube;     //Adding cube to sum of cube(scube)
                p=p/10;
        }
        if(scube==t)
                printf("\nGiven number is armstrong\n");
        else
                printf("\nGiven number is not armstrong\n");
        return;
}

SAMPLE OUTPUT: